Finding the Sum up array having numbers sum[1,n] = n*(n+1)/2
The sum of the squares of the first (n) natural numbers sum[1,n]^2 = n*(n+1)*(2n+1)/6
110 (binary) to (int)
val = val*2 + node.val
at last ans = 6
Finding the Sum up array having numbers sum[1,n] = n*(n+1)/2
The sum of the squares of the first (n) natural numbers sum[1,n]^2 = n*(n+1)*(2n+1)/6
110 (binary) to (int)
val = val*2 + node.val
at last ans = 6